In this program, we have to find the total number of even and odd digits of the given number.

```
#include<stdio.h>
int main()
{
int n,d,even=0,odd=0;
printf("Enter a number : ");
scanf("%d",&n);
while(n>0)
{
d = n % 10;
if(d % 2 == 0)
even++;
else
odd++;
n = n / 10;
}
printf("Total number of even and odd digits in the number are : \n");
printf("Even : %d , Odd : %d \n",even,odd);
return 0;
}
```

```
OUTPUT:
Enter a number : 14523
Total number of even and odd digits in the number are :
Even : 2 , Odd : 3
```